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WombatDialer Soporte en Español / Re: wombat dialer agent page
« on: September 08, 2015, 16:57:33 »
any updated please???
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Hola nuevamente,
como indicado en la respuesta anterior te pedimos que cambie en la pagina:
Antes: [Select]
String[] resLines = AgentsPopupHelper.httpPostToLines(apiReserve, parms);
Cambiar a: [Select]
Aquí tenéis los logs:
Mode:reserve withExtSt
API RESERVE:http://83.170.83.216:8080/wombat/api/reserve/
Aug 24, 2015 10:16:34 AM org.apache.catalina.core.StandardWrapperValve invoke
SEVERE: Servlet.service() for servlet [jsp] in context with path [/wombat] threw exception [An exception occurred processing JSP page /agents/rd_pop.jsp at line 55
52: parms.put("op", "reserve");
53: parms.put("agent", agent);
54: System.out.println( "API RESERVE:" + apiReserve);
55: String[] resLines = AgentsPopupHelper.httpPostToLines(apiReserve, parms);
56:
57: String code = resLines[0];
58: if (code.equalsIgnoreCase("OK: OK")) {
Stacktrace:] with root cause
java.net.ConnectException: Connection timed out
at ch.loway.app.wombat.web.agents.AgentsPopupHelper.httpConnector(AgentsPopupHelper.java:106)
at ch.loway.app.wombat.web.agents.AgentsPopupHelper.httpPostToLines(AgentsPopupHelper.java:116)
at org.apache.jsp.agents.rd_005fpop_jsp._jspService(rd_005fpop_jsp.java:112)
at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
at org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:432)
at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
at org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:305)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:225)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:123)
at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:472)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:168)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:98)
at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:927)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:118)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:407)
at org.apache.coyote.http11.AbstractHttp11Processor.process(AbstractHttp11Processor.java:1002)
at org.apache.coyote.AbstractProtocol$AbstractConnectionHandler.process(AbstractProtocol.java:579)
at org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:310)
at java.util.concurrent.ThreadPoolExecutor$Worker.runTask(Unknown Source)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(Unknown Source)
at java.lang.Thread.run(Unknown Source)
(END)
System.out.println( "API RESERVE:" + apiReserve);
String[] resLines = AgentsPopupHelper.httpPostToLines(apiReserve, parms);
Esto va a mostrar una nueva linea en el stdout (catalina.out) con la URL que está intentando acceder.
Podrías postear la salida aquí ?
Gracias.